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A metal conductor of length 1 m rotates ...

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the e.m.f. developed between the two ends of the conductor is

A

`5 mu V`

B

`50 m V`

C

`5 mV`

D

`50 mu V`

Text Solution

Verified by Experts

The correct Answer is:
D
Induced e.m.f. `=(1)/(2) B omega l^(2)=(1)/(2)xx(0.2xx10^(-4))xx5xx(1)^(2)`
`therefore` Induced e.m.f. `=5xx10^(-5)=50 mu V`
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