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A conducting wire of length l and mass m...

A conducting wire of length l and mass m can slide without friction on two parallel rails and is connected to capacitance C. The whole system lies in a magnetic field B and a constant force F is applied to the rod. Then

A

the rod moves with constant velocity

B

the rod moves with an acceleration of `(F)/(m+B^(2)l^(2)C)`

C

there is constant charge on the capacitor.

D

charge on the capacitor increases with time

Text Solution

Verified by Experts

The correct Answer is:
B, D
Current, `i=(dq)/(dt)=(d)/(dt)(CvBl)=CBl(dv)/(dt)=CBla`
`therefore F-CB^(2)l^(2)a=ma rArr a=(F)/(m+B^(2)l^(2)C)`
`rArr` emf increases `rArr` change increases
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