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In the figure shown in key is switched o...

In the figure shown in key is switched on a t = 0. Let `I_(1)` and `I_(2)` be the current through inductors having self inductances `L_(1)` and `L_(2)` at any time t respectively. The magnetic energy stored in the inductors 1 and 2 be `U_(1)` and `U_(2)`. Then `U_(1)//U_(2)` at any instant of time is

A

`(L_(2))/(L_(1))`

B

`(L_(1))/(L_(2))`

C

`(I_(1))/(I_(2))`

D

`(I_(2))/(I_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A, C
As inductors are in parallel, so
`e_(1)=e_(2)` or `L_(1)(di_(1))/(dt)=L_(2)(di_(2))/(dt)rArr L_(1)i_(1)=L_(2)i_(2)`
Now `(U_(1))/(U_(2))=(e_(1)i_(1))/(e_(2)i_(2))=(i_(1))/(i_(2))=(L_(2))/(L_(1))`
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