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The ratio of contributions made by the e...

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is

A

`c:1`

B

`c^2:1`

C

`1:1`

D

`sqrtc:1`

Text Solution

Verified by Experts

The correct Answer is:
C

As intensity due to electric field `I_E=1/2 cepsilon_0E^2` ,
Intensity due to magnetic field `I_B=(cB^2)/(2mu_0)`
`I_E/I_B=(1/2cepsilon_0E^2)/(cB^2//2mu_0)=(epsilon_0mu_0)(E//B)^2=(1/c^2)(c^2)=1` (as `c=1/sqrt(epsilon_0mu_0` and E/B=c )
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