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Let rho(r) = (Q r)/(piR^4) be the charge...

Let `rho(r) = (Q r)/(piR^4)` be the charge density distribution for a solid sphere of radius R and total charge Q. For a point P inside the sphere at a distance `r_1` from the centre of the sphere, the magnitude of electric field is

A

`Q/(4piepsilon_0r_1^2)`

B

`(Qr_1^2)/(4piepsilon_0R^4)`

C

`(Qr_1^2)/(3piepsilon_0R^4)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C

In figure dotted sphere of radius `r_1` is the Gaussian surface.
According to Gauss.s theorem
`ointvecE.dvecs=q_"inside"/epsilon_0`
`ointE ds cos 0^@=1/epsilon_0 int rho(r) xx dV`
`E(4pir_1^2)xx1=(Qr_1)/(epsilon_0pir^4)xx(4/3pir_1^3)`
`E=(Q. 4pir_1^4)/(3epsilon_0 . piR^4 (4pir_1^2))=(Qr_1^2)/(3piepsilon_0R^4)`
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