A particle of charge q and mass m moves in a circular orbit of radius r with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Options

A. `omega` and q
B. `omega`,q and m
C. q and m
D. `omega` and m

Answer

C

Explanation

Ratio of magnetic moment and angular momentum is given by `M/L=q/(2m)`
which is a function of q and m only. This can be derived as follows
`M=1A = (qupsilon)(pir^2)=(q)(omega/(2pi))(pir^2)=(qomegar^2)/2`
`L=Iomega=(mr^2omega) therefore M/L=(q omegar^2//2)/(mr^2omega)=q/(2m)`