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The equation of the line passing through `(-4, 3, 1),` parallel to the plane `x +2y-z-5=0` and intersecting the line `(x+1)/-3=(y-3)/2=(z-2)/-1`

Answer

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Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

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Knowledge Check

  • The equation of line passing through the point (-4,3,1) parallel to the plane x + 2y-z-5 = 0 and intersect the lien (x+1)/(-3) = (y-3)/(2) = (z-2)/(-1) is.......

    A
    `(x+4)/(-1)(y-3)/1 = (z-1)/(1)`
    B
    `(x+4)/(3) = (y-3)/(1) = (z-1)/(1) `
    C
    `(x-4)/(2) + (y+3)/(1) = (z+1)/(4)`
    D
    `(x+4)/(1) = (y-3)/(1) = (z-1)/(3)`

  • Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

    A
    `(x-1)/1 = (y-1)/2 = (z-1)/1`
    B
    `(x-1)/-1 = (y-1)/1= (z-1)/-1`
    C
    `(x-3)/3 = (y-1)/2 = (z-1)/1`
    D
    `(x-1)/2 = (y-1)/3 = (z-1)/1`

  • Equation of a line passing through (1,-2,3) and parallel to the plane 2x+3y+z+5=0 is

    A
    `(x-1)/(-1)=(y+2)/1=(z-3)/(-1)`
    B
    `(x-1)/2=(y+2)/3=(z-3)/1`
    C
    `(x+1)/(-1)=(y-2)/1=(z-3)/(-1)`
    D
    none of these

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