A particle experiences constant acceleration for 20 seconds after starting from rest.If it travels a distance `S_1` in the first 10 second and `s_2` in the next seconds, how `s_1` and `s_2` are related?

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S_1 and that covered in the first 20 seconds is S_2 then

A body A starts from the rest with an acceleration a_1 . After 2 second another body B starts from rest with an acceleration a_2 . If they travel equal distance in the 5th second after the start of A, then what will be the ratio a_1 : a_2 .

The velocity time relation of an electron starting from rest is given by v=kt where k=2m/s^2 . The distance traversed in 3 second is

A particle of a mass 2 kg moving with a constant acceleration covers a distance of 10 m in the third second and 16 m in the 4th second. What is the initial velocity of the particle?

A particle is dropped under gravity from rest from a height h (g = 9.8m/s^2 ) and it travels and it travels a distance of 9h/25 in the last second the height is

A car starts from rest and moves with constant acceleration. The ratio of the distance covered in the nth second to that covered in n seconds is

The acceleration of a particle starting from rest varies with time according to the relation a=-sw^2 sin wt The displacement of the particle at time 't' will be

Starting from the rest , a body P travels with a uniform acceleration of 4m/s^2 and starting from rest from the same point 4s later , a body Q travels with a uniform acceleration of 16m/s_2 in the same direction as P . Find when and where they meet .