A particle moves in x-y plane according to equations `x=4t^2+5t+16` and `6y=5t`. What is the acceleration of the particle?

Explanation

`x = 4t^2+5t+16` y= 5t
`v_x = dx/dt = 8t+5` v_y =5
`a_x = (dv_x)/dt = 8` (dv_y)/dt = a_y = 0
`a = sqrt(a_x^2+a_y^2) = sqrt(8^2+0)` = 8m / `s^2`