The breaking stress of a cylindrical rod is `10^6 N/m^2`. If the maximum possible height of the rod is 10 m then what is the density of the material of the rod ?

Explanation

Breaking stress = `F//A = (mg)/A = (Vrhog)/A`
`= (A hrhog)/A = hrhog`
`therefore rho = "Breaking stress"/(hg) = 10^6/(10 xx 10) = 10^4 (kg)/m^3`