A piston of cross sectional area `10^-2 m^2` is used in a hydraulic press to exert a force of 100 N on water . What is the cross sectional area of the other piston which supports to carry a mass 2000kg? g =` 9.8m/s^2`

Explanation

From the principle of multiplication forces `(F_1)/(A_1) = (F_2)/(A_2)` in usual symbols `therefore A_2 = F_2 (A_1)/(F_1) = (2000 xx 9.8) xx (10^-2)/(100) = 1.98 m^2`