If a cylinder of diameter of 1 cm at `30^@C` is fitted into a hole of diameter 0.9997 cm in a steel plate, find the temperature the fitting has to be done ? Co.eff.of linear expansion of steal is `12 xx 10^(-6)//^@ C`

A steel rod is 3.000 cm in diameter at 25^@C . A brass ring has an interior diameter of 2.992 cm at 25^@C . At what common temperature will the ring just slide onto the rod ? (Coefficient of linear expansion of steel= 12 xx 10^(-6) per k and coefficient of linear expansion of brass= 18 xx 10^(-6) per k) .

What do you understand by the following statements.Co.efficient of area expansion of a material is 30 xx 10^(-6) per^@C .

A brass disc at a 20^@C has a diameter of 30 cm and a hole cut in the centre is 10 cm in diameter. Calculate the diameter of the hole when temperature of the disc is raised to 50^@C . The coefficient of linear expansion of brass= 0.000018 per^@C .

A clock with a copper pendulum beats seconds at 25^@C . Find the loss or gain perday when the temperature falls to 10^@C . Take co-efficient of linear expansion of copper = 18 xx 10^(-6)//^@ C

An iron plate has a circular hole of diameter 10 cm . Find the diameter of the hole when the plate is uniformly heated from 10^@C to 90^@C (alpha = 12 xx 10^(-6)//^@C) .

A steel tyre is 1 m in diameter at 10^@C . To what temperature it must be raised so that it may just slip on a wheel 1.005 m in diameter ? alpha for steel = 12 xx 10^(-6)//^@C .

What should be the length of steel abd copper rods at 0^@C so that the difference in their lengths is 5.0 cm at all temperatures. Coefficient of linear expansion of copper is 1.7 xx 10^(-5) //^@ C and that of steel is 1.1 xx 10^(-5) //^@ C .

A rod A and a rod B of different materials differ in length by 5 cm at all temperatures . What are their lengths at 0^@C if the coefficients of linear expansion of A and B are 12 xx 10^(-6)//^@C and 18 xx 10^(-6)//^@C respectively ?

A metal sphere 10.01 cm in diameter is placed on a brass ring of internal diameter 10 cm at the same temperature of 12^@C . Find the temperature to which they should be heated together so that the metal sphere just passes through the ring . alpha_"metal" = 12 xx 10^(-6)//^@C and alpha_"brass" = 18 xx 10^(-6)//^@C