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Latent heat of fusion of lead is 5"cal"/...

Latent heat of fusion of lead is `5"cal"/(gm)` and its melting point is `328^@C` .How much heat is required to melt 5 gm of lead initially at `18^@C`? (Specific heat of lead = `0.031"cal"//(gm)//^@C)` .

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MBD PUBLICATION-THERMAL PROPERTIES OF MATTER (HEAT PHENOMENA)-QUESTION BANK
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