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When 25 gm of ice at -20^@C have absorbe...

When 25 gm of ice at -`20^@C` have absorbed 2500 cal of heat, what is the temperature of the resulting water? (latent heat of ice = `80 "cal"//(gm)` and specific heat of ice = `0.5 "cal"//(gm)//^@C)` .

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