A blackened platinum wire is of length 0.1 m and circumference `2 xx 10^(-4) `m. calculate the rate at which the wire is loosing energy if it's temperature is 3000 K .

Explanation

Rate of loss energy = `e sigma T^4 xx A`
Here e = 1 (blackened surface),
`sigma = 5.67 xx 10^(-8) J m^(-2) s^(-1) k^(-4)`
T= 3000K
A = `(2 pi r) xx l = 2 pi (2 xx 10^(-4) ) xx 0.1 m^2`.