If a trolley starts from rest with an accerelaton of `2m/s^(2)`, the velocity of the body after 4 s would be

Options

A. 2m/s
B. 8m/s
C. 4m/s
D. 6m/s

Answer

To solve the problem step by step, we will use the first equation of motion, which relates initial velocity, final velocity, acceleration, and time.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Initial velocity (U) = 0 m/s (since the trolley starts from rest)
- Acceleration (A) = 2 m/s²
- Time (T) = 4 seconds

2. **Use the First Equation of Motion:**
The first equation of motion is given by:
\[ V = U + A \times T \]
where:
- V is the final velocity,
- U is the initial velocity,
- A is the acceleration,
- T is the time.

3. **Substitute the Values into the Equation:**
Now, substitute the known values into the equation:
\[ V = 0 + (2 \, \text{m/s}^2) \times (4 \, \text{s}) \]

4. **Calculate the Final Velocity:**
\[ V = 0 + 8 \, \text{m/s} = 8 \, \text{m/s} \]

5. **State the Final Answer:**
The velocity of the trolley after 4 seconds is **8 m/s**.