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The velocity of a particle increases fro...

The velocity of a particle increases from u to v in a time t during which it covers a distances S. If the particle has a uniform accerelation, which one of the following equations does not apply to the motion?

A

2S=(v+u)t

B

`a=(v-u)/(t)`

C

`v^(2) = u^(2)-2aS`

D

`S=(u+(1)/(2)at)t`

Text Solution

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The correct Answer is:
To solve the problem, we need to identify which equation of motion does not apply to a particle moving with uniform acceleration, given that its velocity changes from \( u \) to \( v \) over a time \( t \) while covering a distance \( S \). ### Step-by-Step Solution: 1. **Understanding the Variables**: - Initial velocity: \( u \) - Final velocity: \( v \) - Time taken: \( t \) - Distance covered: \( S \) - Uniform acceleration: \( a \) 2. **Using the First Equation of Motion**: The first equation of motion relates final velocity, initial velocity, acceleration, and time: \[ v = u + at \] From this, we can express acceleration as: \[ a = \frac{v - u}{t} \] 3. **Using the Second Equation of Motion**: The second equation of motion relates distance, initial velocity, time, and acceleration: \[ S = ut + \frac{1}{2}at^2 \] Substituting \( a \) from the first equation into this gives: \[ S = ut + \frac{1}{2} \left(\frac{v - u}{t}\right)t^2 \] Simplifying this, we get: \[ S = ut + \frac{1}{2}(v - u)t \] Rearranging yields: \[ 2S = (u + v)t \] 4. **Using the Third Equation of Motion**: The third equation of motion relates the velocities and distance: \[ v^2 = u^2 + 2aS \] Substituting \( a \) from the first equation gives: \[ v^2 = u^2 + 2\left(\frac{v - u}{t}\right)S \] 5. **Identifying the Incorrect Equation**: The options provided include: - \( v^2 = u^2 + 2aS \) - \( v^2 = u^2 - 2S \) (This option is incorrect because it suggests a negative relationship which does not apply in this context) - \( S = ut + \frac{1}{2}at^2 \) - \( 2S = (u + v)t \) The equation \( v^2 = u^2 - 2S \) is not applicable because it does not correctly represent the relationship between the variables when acceleration is positive. The correct form should be \( v^2 = u^2 + 2aS \). ### Conclusion: The equation that does not apply to the motion is: \[ \text{Option C: } v^2 = u^2 - 2S \]

To solve the problem, we need to identify which equation of motion does not apply to a particle moving with uniform acceleration, given that its velocity changes from \( u \) to \( v \) over a time \( t \) while covering a distance \( S \). ### Step-by-Step Solution: 1. **Understanding the Variables**: - Initial velocity: \( u \) - Final velocity: \( v \) - Time taken: \( t \) ...
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MCGROW HILL PUBLICATION-MOTION-HIGHER ORDER THINKING QUESTIONS
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