Home
Class 10
PHYSICS
Area under a velocity-time graph gives...

Area under a velocity-time graph gives

A

the time taken by a moving object

B

the distance travelled by a moving object

C

the acceleration of moving object

D

the retardation of a moving object

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding what the area under a velocity-time graph represents, we can follow these steps: ### Step 1: Understand the Definitions - **Velocity (v)** is defined as the rate of change of displacement with respect to time. Mathematically, this can be expressed as: \[ v = \frac{ds}{dt} \] where \( ds \) is the change in displacement and \( dt \) is the change in time. ### Step 2: Rearranging the Equation - By rearranging the above equation, we can express \( ds \) in terms of \( v \) and \( dt \): \[ ds = v \cdot dt \] ### Step 3: Integrating Over Time - To find the total displacement over a time interval, we can integrate both sides: \[ \int ds = \int v \, dt \] This means that the total displacement \( s \) is equal to the integral of velocity over time. ### Step 4: Area Under the Curve - The integral of velocity \( v \) with respect to time \( t \) gives us the area under the velocity-time graph. Therefore: \[ s = \int v \, dt \] This indicates that the area under the velocity-time graph corresponds to the total displacement. ### Step 5: Conclusion - Thus, the area under a velocity-time graph gives us the **displacement** of the object over the time interval considered. If the motion is in a straight line and the velocity is constant, this displacement will also equal the distance traveled. ### Final Answer The area under a velocity-time graph gives **displacement**. ---
Promotional Banner

Topper's Solved these Questions

  • MOTION

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|48 Videos
  • MISCELLANEOUS QUESTIONS

    MCGROW HILL PUBLICATION|Exercise PART-B|99 Videos
  • REFLECTION OF LIGHT

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

Assertion: Area under velocity-time graph give displacement. Reason: Area under acceleration-time graph give velocity.

Draw the velocity-time graph for an object in uniform motion. Show that the area under the velocity-time graph gives the displacement of the object in the given time interval.

[" The acceleration of a "],[" moving body can be found "],[" from "],[" (A) Area under velocity - time graph "],[" (B) Area under distance - time graph "],[" (C) Slope of the velocity - time graph "],[" (D) Slope of distance - time graph "]

1.The acceleration of a moving body can be found from (A) Area under velocity-time graph (B) Area under distance-time graph (C) Slope of the velocity-time graph (D) Slope of distance-time graph

Assertion: The displacement of a body is vector sum of the area under velocity-time graph. Reason: Displacement is a vector quantity.

Show that area under the velocity-time graph of an object moving with constant acceleration in a straight line in certain time interval is equal to the distance covered by the object in the interval.

Show that the area under the velocity-time graph of an object moving with constant acceleration in a straight line in certain time interval is equal to the distance covered by the object in that interval.

Draw velocity-time graph of a uniformly accelerated in one dimension and explain that the distance travelled is equal to the area under velocity-time graph.

Draw velocity-time graphof uniform motion and prove that the area under the velocity-time graph of a particle gives the displacement of the particle in a given time.

MCGROW HILL PUBLICATION-MOTION-HIGHER ORDER THINKING QUESTIONS
  1. Area under a velocity-time graph gives

    Text Solution

    |

  2. The location of a particle has changed. What can you say about the dis...

    Text Solution

    |

  3. A train 120m long is going towards north direction at a speed of 8ms^(...

    Text Solution

    |

  4. Which of the following velocity-time graphs does not represent motion ...

    Text Solution

    |

  5. A boy completes one round of a circular track of radius r in 40 s. His...

    Text Solution

    |

  6. A particle starts from the origin, goes along X-axis to the point (30m...

    Text Solution

    |

  7. A car runs on a circular track at a constant speed. The circular track...

    Text Solution

    |

  8. In question 68 above, the average velocity of the car is

    Text Solution

    |

  9. Which of the following distance-time graphs is not possible?

    Text Solution

    |

  10. Two persons start running towards each other from two points that arc ...

    Text Solution

    |

  11. In question 71 above, two persons meet each other from the first point...

    Text Solution

    |

  12. If a car at rest accelerates uniformly to a speed of 144km/h 20 s, it ...

    Text Solution

    |

  13. A body starting from rest is moving with a uniform acceleration of 8m/...

    Text Solution

    |

  14. A 120 m long train is moving in a direction with a speed of 20ms^(-1)....

    Text Solution

    |

  15. A bullet is fired with a speed of 10^(3)ms^(-1) in order to hit s targ...

    Text Solution

    |

  16. A car moves for half of its time at 80 km//h and for rest of time at 4...

    Text Solution

    |

  17. The distance (5) travelled varies with time (t) for four different-bod...

    Text Solution

    |

  18. The area under acceleration-time graph gives

    Text Solution

    |

  19. The displacement of a body is given to be proportional to the cube of ...

    Text Solution

    |

  20. Fig. 3.39 shows the acceleration - time graph for a particle in rectil...

    Text Solution

    |

  21. A body nis thrown vertically upward. Which of the following graphs cor...

    Text Solution

    |