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CaCO3 + 2HCl to CaCl2 + H2O + CO2 The...

`CaCO_3 + 2HCl to CaCl_2 + H_2O + CO_2`
The mass of calcium chloride formed when 2.5 g calcium carbonate are dissolved in excess of hydrochloric acid is

A

1.39g

B

2.78g

C

5.18g

D

17.8g

Text Solution

Verified by Experts

The correct Answer is:
B
`CaCO_3 + 2HCl to CaCl_2 + H_2O + CO_2`
`100g CaCO_3 ` given 111g `CaCl_2`
`therefore 2.5g CaCO_3` given `111/100 xx 2.5`
` = 2.78 g CaCl_2`
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