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The volume of 8 g O(2) at STP is...

The volume of 8 g `O_(2)` at STP is

A

22.4 L

B

11.2 L

C

5.6 L

D

2.24 L

Text Solution

Verified by Experts

Number of moles of `O_(2)=(8)/(32)=(1)/(4)=0.25`
Volume of 1 mole of `O_(2)` at STP = 22.4 L
`therefore` Volume of 0.25 mole of `O_(2)` at STP
`=22.4" "0.25=5.6L`
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