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The angle between two covalet bonds is m...

The angle between two covalet bonds is minimum in

A

`CH_(4)`

B

`C_(2)H_(2)`

C

`NH_(3)`

D

`H_(2)O`

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The correct Answer is:
To determine the minimum angle between two covalent bonds, we need to analyze the molecular geometries and bond angles of various compounds. Let's evaluate the bond angles in different molecules step by step. ### Step 1: Identify the Molecules We will consider the following molecules: 1. Methane (CH₄) 2. Ethene (C₂H₄) 3. Ammonia (NH₃) 4. Water (H₂O) ### Step 2: Analyze the Bond Angles - **Methane (CH₄)**: The structure of methane is tetrahedral, and the bond angle between the hydrogen atoms is approximately **109.5 degrees**. - **Ethene (C₂H₄)**: Ethene has a planar structure due to the presence of a double bond, and the bond angle is **120 degrees**. - **Ammonia (NH₃)**: Ammonia has a trigonal pyramidal shape, and the bond angle is around **107 degrees**. - **Water (H₂O)**: Water has a bent shape, and the bond angle is approximately **104.5 degrees**. ### Step 3: Compare the Bond Angles Now we compare the bond angles we have identified: - Methane (CH₄): 109.5 degrees - Ethene (C₂H₄): 120 degrees - Ammonia (NH₃): 107 degrees - Water (H₂O): 104.5 degrees ### Step 4: Determine the Minimum Angle From the bond angles listed, we can see that: - The bond angle in water (H₂O) is the smallest at **104.5 degrees**. ### Conclusion The angle between two covalent bonds is minimum in **water (H₂O)**. ---

To determine the minimum angle between two covalent bonds, we need to analyze the molecular geometries and bond angles of various compounds. Let's evaluate the bond angles in different molecules step by step. ### Step 1: Identify the Molecules We will consider the following molecules: 1. Methane (CH₄) 2. Ethene (C₂H₄) 3. Ammonia (NH₃) 4. Water (H₂O) ...
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