Heating sodium ethanoate with sosa lime gives

Options

A. methane
B. ethane
C. propane
D. ethene

Explanation

To solve the question of what product is obtained by heating sodium ethanoate with sodalime, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
- Sodium ethanoate (CH₃COONa) is the sodium salt of acetic acid.
- Sodalime is a mixture of sodium hydroxide (NaOH) and calcium oxide (CaO). It is commonly used as a dehydrating agent and also facilitates decarboxylation reactions.

2. **Understand the Reaction:**
- When sodium ethanoate is heated with sodalime, a decarboxylation reaction occurs. Decarboxylation is the removal of a carboxyl group (-COOH) from a compound, releasing carbon dioxide (CO₂).

3. **Write the Reaction:**
- The reaction can be represented as:
\[ \text{CH}_3\text{COONa} \xrightarrow{\text{sodalime}} \text{CH}_4 + \text{Na}_2\text{CO}_3 \]
- Here, sodium ethanoate (CH₃COONa) is converted into methane (CH₄) and sodium carbonate (Na₂CO₃).

4. **Identify the Products:**
- The primary product of this reaction is methane (CH₄), which is an alkane.

5. **Conclusion:**
- Therefore, the product obtained by heating sodium ethanoate with sodalime is methane (CH₄).

### Final Answer:
The product obtained by heating sodium ethanoate with sodalime is **methane (CH₄)**.