1.80 g of glucose (molar mas =180) is dissolved in 36.0 g of water in a beaker. The total number of oxygen atoms in the solution is

Options

A. `12.405xx10^(23)`
B. `12.405xx10^(22)`
C. `6.022xx10^(23)`
D. `6.022xx10^(22)`

Answer

To find the total number of oxygen atoms in the solution containing 1.80 g of glucose and 36.0 g of water, we can follow these steps:

### Step 1: Calculate the number of moles of glucose.
The formula to calculate the number of moles is:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
For glucose (C₆H₁₂O₆):
- Given mass = 1.80 g
- Molar mass = 180 g/mol

Calculating the number of moles of glucose:
\[ \text{Number of moles of glucose} = \frac{1.80 \, \text{g}}{180 \, \text{g/mol}} = 0.01 \, \text{mol} \]

### Step 2: Calculate the number of moles of water.
For water (H₂O):
- Given mass = 36.0 g
- Molar mass = 18 g/mol

Calculating the number of moles of water:
\[ \text{Number of moles of water} = \frac{36.0 \, \text{g}}{18 \, \text{g/mol}} = 2.0 \, \text{mol} \]

### Step 3: Calculate the number of oxygen atoms from glucose.
In one molecule of glucose (C₆H₁₂O₆), there is 1 oxygen atom. Therefore, the number of oxygen atoms from glucose can be calculated by:
\[ \text{Number of oxygen atoms from glucose} = \text{Number of moles of glucose} \times \text{Avogadro's number} \]
\[ = 0.01 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 6.022 \times 10^{21} \, \text{oxygen atoms} \]

### Step 4: Calculate the number of oxygen atoms from water.
In one molecule of water (H₂O), there is 1 oxygen atom. Therefore, the number of oxygen atoms from water can be calculated by:
\[ \text{Number of oxygen atoms from water} = \text{Number of moles of water} \times \text{Avogadro's number} \]
\[ = 2.0 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 1.2044 \times 10^{24} \, \text{oxygen atoms} \]

### Step 5: Calculate the total number of oxygen atoms in the solution.
Now, we can add the number of oxygen atoms from glucose and water:
\[ \text{Total number of oxygen atoms} = \text{Oxygen atoms from glucose} + \text{Oxygen atoms from water} \]
\[ = 6.022 \times 10^{21} + 1.2044 \times 10^{24} \]
\[ = 1.210462 \times 10^{24} \, \text{oxygen atoms} \]

### Final Answer:
The total number of oxygen atoms in the solution is approximately \( 1.210 \times 10^{24} \).

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