The work done in increasing the size of a rectangular soap film with dimensions 8cm times3.75cm to 10cm times6cm is 2times10^(-4)J .The surface tension of the film in N/m is

The work done in increasing the size of a rectangular soap film with dimensions 8 cm x 3.75 cm to 10 cm x 6 cm is 2 xx 10^(-4) J . The surface tension of the film in (N m^(-1)) is

The work done in increasing the size film with dimensions 8cm xx3.75xm to 10cmxx6cm is 2xx10^(-4)J . The surface tension of the film in (N)/(m) is

The work done in increasing the size of a soap film from 10 cm × 6 cm to 10 cm × 11 cm is 3 xx10^(-4) joule . The surface tension of the film is

The workdone in increasing the size of a soap film from 10 cm xx 6 cm to 10 cm xx 11 cm is 3 xx 10^(-4)J. The surface tension of the film is

If work done in increasing the size of a soap film from 10 cm x 6 cm to 10 cm x 11 cm is 2xx10^(-4) J , then the surface tension is

The work done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm is 3xx10^-4 Joule. The surface tension of the film is

Assertion : if work done in increasing th size of a soap film from 10 cm xx 4 cm to 10cm xx8cm is 2xx10^(-4) J, then the surface tension is 5xx10^(-4)N m^(-1) Reason : work done = surface tension xx increase in area .

Work of 6.0xx10^(-4) N joule is required to the done in increasing the size of soap film form 10cmxx6cm to 10cmxx11cm . The surface tension of the film is (in N//m)

If work done in increasing the size of a soap film from 10cmxx6cmxx to 10cmxx11xm is 2xx10^-4H , then the surface tension is

What is the volume of a cuboid of dimensions 2.8 cm times 1.6 cm times 4 cm?