`(dy)/(dx) + 2 y tan x = sin x `

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(dy)/(dx) = y tan x - 2 sinx

The solution of the differential equation (dy)/(dx) = y tan x - 2 sin x , is

(dy) / (dx) + 2tan x * y = sin x

(dy)/(dx)+y tan x=sec x

Solve each of the following initial value problem: (dy)/(dx)=2y tan x=sin x;y=0 when x=(pi)/(3)

(dy) / (dx) tan y = sin (x + y) + sin (xy)

The solution of the differential equation (dy)/(dx)=y tan x-2sin x is

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to:

(dy)/(dx)+y sec x=tan x

sec ^ (2) y (dy) / (dx) + x tan y = x ^ (3)