If `P (E) = 0.05,` what is the prabability of 'not' E' ?

If P(E) = 0.20, then the probability of 'not E' is:

If P(A)=0.05 the P(bar(A)) is

Of the three independent events E_(1),E_(2),and E_(3), the probability that only E_(1) occurs is alpha only E_(2) occurs is beta, and only E_(3) occurs is gamma. Let the probability p that none of events E_(1),E_(2), or E_(3) occurs satisfy the equations (alpha-2beta)p=alpha betaand (beta-3gamma)p=betagamma. All the given probabilities are assumed to lie in the interval (0,1). Then ("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=______.

A random varticle X has the probability distribution : {:(X:,1,2,3,4,5,6,7,8),(P(X):,0.150.23,,0.12,0.10,0.20,0.08,0.07,0.05):} For the events E = {X is a prime number } and F = { X lt 4} , the probability P( E cup F) is :

Events E and F are uch that P(not E or not F) = 0.25 , State whether E and F are mutually exclusive.

There are n students in a class. Ler P(E_lambda) be the probability that exactly lambda out of n pass the examination. If P(E_lambda) is directly proportional to lambda^2(0lelambdalen) . Proportional constant k is equal to

If P(A)=0.8, P(B)=0.5 , then P(AcapB) lies in the interval

A rectangular coil of 100 turns and size 0.1 m xx 0.05 m is placed perpendicular to a magnetic field of 0.1 T. If the field drops to 0.05 T in 0.05 second, the magnitude o the e.m.f. induced in the coil is