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lambda(m)^(@) for NaCl, HCl and CH(3)COO...

`lambda_(m)^(@)` for `NaCl, HCl and CH_(3)COONa` are 126.4,425.9 and `"91.0 S cm"^(2)//"mol"` respectively. Calculate `lambda_(m)^(@)" for "CH_(3)COOH`.

Text Solution

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`lambda_(m_(CH_(3)COOH))^(@)=lambda_(CH_(3)COONa)^(@)+lambda_(HCl)^(@)-lambda_(NaCl)^(@)=91+425.4-126.4=390.5scm^(3)//mol`
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