A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84 g in 100g of water at 298K. Calculate the freezing point of water in the solution. `(K_f for water = 1.86 K kg mol^-1)`

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84 g in 100g of water at 298K. Calculate the boiling point of water in the solution (K_b for water = 0.52 K kg mol^-1)

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 6.84g in 100g of water at 298K. Calculate the freezing point of the solution ( K_f for water, 1.86K Kgmol^-1 ).

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 6.84g in 100g of water at 298K. Calculate the boiling point of the solution. ( K_b for water, 0.52K mol^-1 )

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 6.84g in 100g of water at 298K. Calculate the osmotic pressure of the solution at 298K (Density of water at 298K + 1 g mL^-1 ).

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84g in100 g of water at 298 K. Calcuate the osmotic pressure of the solution at 298 K (Density of water at 298 K = 1 gmol^-1)

Calculate the freezing point of an aqueous solution containing 10.50g of MgBr_2 = 184g, K_f for water = 1.86 K kg mol^-1 .

0.52g of glucose (C_6H_12O_6) is dissolved in 80.2g of water calculate the boiling point of the solution. ( K_b for water is 0.52 K kg mol^-1 ).

What mass of NaCl (molar mass= 58.5g mol^-1) must be dissolved in 65g of water to lower the freezing point by 7.5^@C ? The freezing point depression constant, K_f for water is 1.86 K kg mol^-1 . Assume vant Hoff factor for NaCl is 1.87.

A 0.1539 molal aqueous solution of canesugar (molar mass = 342g mol^-1) has a freezing point 271K. While the freezing point of pure water is 273.15k. What will be the freezing point of an aqueous solution, containing 5g of glucose (Mol mass = 180g mol^-1) per 100g of solution?

A 5% solution (by mass) of canesugar in water has freezing point of 271K. Calculate the freezing point of a 5% glucose in water if freezing point of pure water is 273.15K.