Why is freezing point depression of 0.1 M sodium chloride solution nearly twice that of 0.1 M Glucose solution?

The conductance of 0.1 M HCl solution is greater than that of 0.1 M NaCl. Why?

How is it that the elevation in boiling points of the following solutions in water are different? 0.1 M NaCl solution 0.1 M Sugar solution.

1.0 g of a nonelectrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol. Find the molar mass of the solute.

Which of the following pairs will have greater conduction ? 0.1M NaCl solution at 25^@C and 0.1M NaCl solution at 50^@C .

Which of the following pairs will have greater conduction ? 0,1M acetic acid solution or 1m acetic acid solution.

0.01M solution of KCl and BaCl_2 are prepared in water. The freezing points of KCl is found to be -2^@C . What freezing point would you expect for BaCl_2 solution assuming both KCl and BaCl_2 to be completely ionised?

A 0.1539 molal aqueous solution of canesugar (molar mass = 342g mol^-1) has a freezing point 271K. While the freezing point of pure water is 273.15k. What will be the freezing point of an aqueous solution, containing 5g of glucose (Mol mass = 180g mol^-1) per 100g of solution?

Give reasons for the following Resistance of a conductivity cell filled with 0.1M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02M KCl solution is 520 Omega . Calculate the conductivity and molar conductivity of 0.02M KCl solution. Conductivity of 0.1M KCl solution in 1.29 S//m .

A solution of glucose in water in labelled as 10% w//w , what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL^-1 , then what shall be the molarity of the solution?

A 5% solution (by mass) of canesugar in water has freezing point of 271K. Calculate the freezing point of a 5% glucose in water if freezing point of pure water is 273.15K.