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A 0.1539 molal aqueous solution of canes...

A 0.1539 molal aqueous solution of canesugar `(molar mass = 342g mol^-1)` has a freezing point 271K. While the freezing point of pure water is 273.15k. What will be the freezing point of an aqueous solution, containing 5g of glucose `(Mol mass = 180g mol^-1)` per 100g of solution?

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