Derive the relation between the relative lowering of vapour pressure and mole fraction of the volatile liquid.

What is meant by "Relative lowering of Vapour pressure".

What is the effect of temperature on the vapour pressure of a liquid?

A man walking briskly in, rain with speed v must slant his umbrella forward making an angle theta with the vertical. A student derives the following relation between theta and v, tantheta = v and checks that the relation has a correct limit: as v rarr 0, theta rarr -0 , as expected.. (We are assuming there is no strong wind and that the rain falls vertically for a stationary man). Do you think this relation can be correct? If not, guess the correct relation.

The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.

What concentration of nitrogen should be present in a glass of water at room temperature at 25^@C , a total pressure of 1 atm and mole fraction on nitrogen in air of 0.78 [ K_H for nitrogen = 8.42xx10^(-7)M//mmHg ].

100 g of liquid A (molar mass 140 g mol^-1) was dissolved in 1000g of liquid B (molar mass 180 g mol^-1) . The vapour pressure of pure liquid B was found to be 500 torr: Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.

State the formula relating pressure of a gas with its mole fraction in a liquid solution in contact with it.

Solution of two volatile liquids A and B obey Roalt's law. At certain temperature, it is found that when the toal pressure above a solution is 0.53 bar. The mol fraction. A in the vapour is 0.45 & other liquid is 0.65. What are the vapour pressures of the two pure liquids at the given temperature?

A plot is obtained for two volatile liquids A & B as follows. From the plot answer the following. What is the mol fraction of vapour phase of componant A over the solution?

Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toulene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.