Knowing the equilibrium constant value of a cell reaction at a particular temperature, how will you calculate the standard Gibbs free energy change for the reaction?

Write the correct relationship between Gibb's free energy change and the emf of the cell.

The rate constant of a reaction at 500K and 700K are 0.01s^-1 and 0.07s^-1 respectively. Calculate the value of activation energy for the reaction (R = 8.314 JK^-1mol^-1).

In general it is observed that the rate of a chemical reaction doubles with every 10^@ rise in temperature. If the generalisation holds for a reaction in the temperature range 295K to 305K, what would be the value of activation energy for the reaction?

The standard electrode potential for Daniel cell is 1.1V. Calculate the standard Gibb's energy for the reaction. Zn_(s)+ Cu_(aq)^(2+) rarr Zn_(aq)^(2+)+Cu_(s) .

At 60^C dinitrogen tetroxide in 50% dissociated.Calculate the standard free energy change at this temperature under 1 atm pressure.

The rate of reaction triples when temperature change from 20^@C to 50^@C . Calculate the energy of activation. (R = 8.314 Jmol^-1K^-1)

The rate constant of reaction is 1.5xx10^7s^-1 at 50^@C and 4.5xx10^7s^-1 at 100^@C . Calculate the value of activation energy for the energy for the reaction (R = 8.314 Jk^-1 mol^-1)

The rate constants of a reaction at 500K and 700K are 0.02s^-1 and 0.07s^-1 respectively. Calculate value of activation energy for the reaction. (Given R = 8.314 JK^-1 mol^-1)

Establish the relationship between standard Gibbs free energy change and equilibrium constant value for a particular electrochemical cell reaction.

The cell in which the following reaction occur. 2Zn(s)+2Cu^(2+)(aq) rarr 2Zn^(2+)(aq)+2Cu(s)E_(cell)^@=1.10 volt at 298K. Calculate the standard Gibbs energy and the equilibrium constant.