Following are the data of standard reduction half cell potentials of certain electrochemical cells.
`E_(Ag^(+)//Ag)^@ = 0.80V & E_(Cu^(2+)//Cu)^@ = 0.34V`
``E_(Sn^(2+)//Sn)^@ =-0.14V & E_(Na^(2+)//Na)^@ = -2.71V` Represent the electrochemical cell constructed from these pair of half cells.

Following are the data of standard reduction half cell potentials of certain electrochemical cells. E_(Ag^(+)//Ag)^@ = 0.80V & E_(Cu^(2+)//Cu)^@ = 0.34V E_(Sn^(2+)//Sn)^@ =-0.14V & E_(Na^(2+)//Na)^@ = -2.73V Calculate the standard EMF of the cells.

Following are the data of standard reduction half cell potentials of certain electrochemical cells. E_(Ag^(+)//Ag)^@ = 0.80V & E_(Cu^(2+)//Cu)^@ = 0.34V E_(Sn^(2+)//Sn)^@ =-0.14V & E_(Na^(2+)//Na)^@ = -2.74V Also identify andode, cathode and direction of flow of current in each of the constructed cells.

Fe^(3+)+e rarr Fe^(2+)_(aq) , E^@ = -0.77V Write the reaction which could be feasible using above half cells.

Given the standard electrode potential value of some metals. K^(+)//K = -2.93V , Ag^(+)//Ag = 0.80V , Hg^(+)//Hg = 0.79V , Mg^(2+)//Mg + -2.37V , Cr^(3+)//Cr = -0.74V . Arrange these metals in their increasing order of reducing power.

Write the Nernst equation and calculate the emf of the following at 298K. Cu(s)|Cu^(2+)(0.13M)||Ag^+(1xx10^-4M)|Ag(s) Given E_(Cu^(2+)//Cu)^@ = 0.34V and E_(Ag^+//Ag)^@ = 0.80V

Can we use a Copper Vessel to store 1M AgNO_3 solution? Given that E_(Cu^(2+)//Cu)^@ = 0.34v and E_(Ag^(+)//Ag)^@ = 0.80v

Which is a stronger reducing agent Zn or Fe? If E_(Zn^(2+)//Zn)^@ = -0.76V , and E_(Fe^(2+)//Fe = -0.44V

Given the standard electrode potentials: k^+//k = -2.93v , Ag^+//Ag = 0.80v , Hg^(2+)//Hg = 0.79v , Mg^(2+)//Mg = -2.37v, Cr^(3+)//Cr = -0.74v Arrange these metals in their increasing order of reducing power.

Given the standard electrode potential value of some metals K^+//K = -2.93V,Ag^+//Ag=0.80V , Hg^(2+)//Hg= 0.79V , Mg^(2+)/MG=-2.37V , Cr^(3+)//Cr=-0.74V Arrange these metals in their increasing order of reducing power.

The electrode potentials for the two half cell reaction is given below. Determine emf Mg^(2+)+2e^- rarr Mg(s), E=-2.37V Cu^(2+)+2e^- rarr Cu(s), E=+0.34V.