The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 O. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is `0.146xx10^-3 S//cm`.

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Omega . What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146xx10^-3 S//cm .

Give reasons for the following Resistance of a conductivity cell filled with 0.1M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02M KCl solution is 520 Omega . Calculate the conductivity and molar conductivity of 0.02M KCl solution. Conductivity of 0.1M KCl solution in 1.29 S//m .

The conductivity of 0.20M solution of KCl at 298K is 0.0248 S//cm .Calculate its molar conductivity.

The conductivity of 0.20M solution of KCl at 298K is 0.0248 Scm-1 . Calculate its molar conductivity.

The conductivity of 0.20M solution of KCL at 298K is 0.0248Scm^-1 , Calculate its molar conductivity.

A monoprotic acid in a 0.1M solution ionizes to 0.001%. Its ionization constant is

The conductance of 0.1 M HCl solution is greater than that of 0.1 M NaCl. Why?

Conductivity of 0.00241 M acetic acid is 7.896xx10^-5 S cm^-1 .Calculate its molar conductivity and what is its dissociation constant?

The conductivity of 0.001M acetic acid is 4X10^(-2)S//m . Calculate the dissociation constant of acetic acid if lambda_m^@ for acetic acid is 390Scm^2mol^(-1) .

Which of the following pairs will have greater conduction ? 0.1M NaCl solution at 25^@C and 0.1M NaCl solution at 50^@C .