Define : Internal resistance

Describe with the help of neat diagram how will you determine the internal resistance of a cell by using potentiometer. Derive the necessary formula.

In an experiment to determine the internal resistance of a cell of emf 1.5 V, the balance point in the open cell condition is 76.3 cm. When a resistor of 9.5 ohm is used in the external circuit of the cell the balance point shifts to 64.8 cm of the potentiometer wire. Determine the internal resistance of the cell.

In potentiometer experiment to determine internal resistance of the cell, balance point has been obtained in fourth wire. It can be shifted to 5^("th") wire by

Name the device used for the measurement of internal resistance of a cell.

Explain the use of potentiometer for determining he internal resistance of cell.

Choose correct alternative. The internal resistance of a cell of emf 2V is 0.1 Omega . It is connected to a resistance of 0. 9 Omega . The voltage across the cell will be.

Choose correct alternative. The internal resistance of an ideal cell is A. zero B. 1Ω C. infinite D. changes irregularly

When a balance point is obtained in a potentiometer for finding the internal resistance of a cell, the current through the potentiometer wire is due to