Is internal resistance a defect of a cell? Explain.

On what factors does the internal resistance of a cell depend?

A potentiometer wire of length 4 m and resistance 8 Omega is connected in, series with a battery of e.m.f. 2 V and negligible internal resistance. If the e.m.f. of cell balances against length of 217 cm of the wire, find the e.m.f. of cell. When the cell is shunted by assistance of 15 Omega ,the balancing length is reduced to 200 cm. Find the internal resistance of the cell

Why there is no way to separate the internal resistance from the e.m.f. of a cell?

Define : Internal resistance

The formula for internal resistance of a cell

A potentiometer circuit has been setup for finding. The internal resistance of a given cell. The main battery used a negligible internal resistance. The potentiometer wire itsefl is 4 m long. When the resistance, R , connected across the given cell, has value of (i) Infinity 9.5 Omega , (ii) the 'balancing length' , on the potentiometer wire are found to be 3 m and 2.85 m , respectively. The value of internal resistance of the cell is

Choose correct alternative. The internal resistance of an ideal cell is A. zero B. 1Ω C. infinite D. changes irregularly

In potentiometer experiment to determine internal resistance of the cell, balance point has been obtained in fourth wire. It can be shifted to 5^("th") wire by

Figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell.The balance point of the cell in open circuit is 76.3 cm.When a resistor of 9.5 Omega is,used in the external circuit of the cell,the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.

The internal resistance of the cell can be determine by,