In a balanced meterbridge, the segment of wire opposite to `20Omega` is 40cm. Calculate the unknown resistance.

In a balanced metre bridge , the segment of wire opposite to a resistance of 70 Omega is 70 cm . The unknown resistance is

In balanced meter bridge, the resistance of bridge wire is 0.1Omega cm . Unknown resistance X is connected in left gap and 6Omega in right gap, null point divides the wire in the ratio 2:3 . Find the current drawn the battery of 5V having negligible resistance

The unknown resistance is placed in a left gap and a resistance of 50 Omega in right gap of meter bridge. The null point is obtained at 60 cm from the right gap. Determine the unknown resistance.

A uniform wire is cut into two pieces such that on piece is twice as long as the other. The two piece are connected in parallel in the left gap of a meterbridge. When a resistance of 20Omega is connected in the right gap, the null point is obtained at a distance of 60cm from the right end of the wire. Find the resistance of the wire before it was cut into two pieces.

In a meter bridge experiment null point is obtained at 20 cm. from one end of the wire when resistance X is balanced against another resistance Y. If X lt Y, then where will be the new position of the null point from the same end, if one deicdes to balance a resistance of 4 X against Y

The e.m.f. of a cell is balanced by fall of potential along 281 cm of potentiometer wire. If a resistance of 8 Omega is connected across the cell , the balancing length is found to be 151 cm. Calculate internal resistance of a cell.

Choose correct alternative. A uniform copper wire of resistance 5 Omega is uniformly stretched, doubled the new resistance of the wire will be

Two resistances are connected in the two gaps of a meter bridge. The balance point is 20 cm from the zero end. When a resistance 15 Omega is connected in series with the smaller of two resistance, the null point+ shifts to 40 cm . The smaller of the two resistance has the value.

In a meter bridge experiment, the unknown resistance X in the left gap and a known resistance of 60 Omega in right gap, null point is obtained at l cm from left. If the unknown resistance X is shunted by an equal resistance, what should be the value of known resistance in the right gap in order to get the null point at the same place?

The combined resistance of a galvanometer of resistance 500Omega and its shunt is 21Omega . Calculate the value of shunt.