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The potentiometer wire has length 10m an...

The potentiometer wire has length 10m and resistance `10Omega`, if the current flowing through it is 0.4A, what are the balancing lengths when two cells of emfs 1.3V and 1.1V are connected so as to:- oppose each other?

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The potentiometer wire has length 10m and resistance 10Omega , if the current flowing through it is 0.4A, what are the balancing lengths when two cells of emfs 1.3V and 1.1V are connected so as to:- assist and

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CHETANA PUBLICATION-Current Electricity-Exercise
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  2. The potentiometer wire has length 10m and resistance 10Omega, if the c...

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  3. The potentiometer wire has length 10m and resistance 10Omega, if the c...

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  4. When a resister of 10Omega is connected across a cell, its terminal po...

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  5. Two cells having unknown emfs E1 and E2 (E1 > E2) are connected in pot...

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  6. A potentiometer wire has a length of 2m and resistance 10Omega. It is ...

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  7. Four resistance 4,4,4 and 12Omega form a Wheatstone’s network. Find th...

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  8. Two resistance x and y in the two gaps of a meter bridge give a null p...

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  9. Three cells are connected in parallel with their like poles connected ...

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  10. The unknown resistance is placed in a left gap and a resistance of 50 ...

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  11. In a meter bridge experiment, the unknown resistance X in the left gap...

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  12. Select and wrote only the correct answer in words alongwith the alphab...

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  13. When the balance point is obtained in the potentiometer, a current is ...

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  14. In the following circuit diagram , an infinite series of resistance is...

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  15. Four resistances 10 Omega, 10 Omega, 10 Omega and 15 Omega form a Whea...

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  16. A circular loop has a resistance of 40 Omega. Two points P and Q of th...

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  17. To find the resistance of a gold bangle, two diametrically opposite po...

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  18. Kirchhoff's second law is the consequence of law of conservation of .....

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  19. For given Wheatstone's network for being balanced, the value of resist...

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  20. In the measurement of resistance by meter bridge, the end error can be...

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