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Two cells having unknown emfs E1 and E2 ...

Two cells having unknown emfs `E_1` and `E_2` `(E_1 > E_2)` are connected in potentiometer circuit so as to assist each other. The null point is obtained at 8.125m from higher potential end. When cell `E_2` is connected so as to oppose cell `E_1`, the null point is obtained at 1.25m from the same end compare the emfs of two cells.

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CHETANA PUBLICATION-Current Electricity-Exercise
  1. The potentiometer wire has length 10m and resistance 10Omega, if the c...

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  2. When a resister of 10Omega is connected across a cell, its terminal po...

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  3. Two cells having unknown emfs E1 and E2 (E1 > E2) are connected in pot...

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  4. A potentiometer wire has a length of 2m and resistance 10Omega. It is ...

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  5. Four resistance 4,4,4 and 12Omega form a Wheatstone’s network. Find th...

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  6. Two resistance x and y in the two gaps of a meter bridge give a null p...

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  7. Three cells are connected in parallel with their like poles connected ...

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  8. The unknown resistance is placed in a left gap and a resistance of 50 ...

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  9. In a meter bridge experiment, the unknown resistance X in the left gap...

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  10. Select and wrote only the correct answer in words alongwith the alphab...

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  11. When the balance point is obtained in the potentiometer, a current is ...

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  12. In the following circuit diagram , an infinite series of resistance is...

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  13. Four resistances 10 Omega, 10 Omega, 10 Omega and 15 Omega form a Whea...

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  14. A circular loop has a resistance of 40 Omega. Two points P and Q of th...

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  15. To find the resistance of a gold bangle, two diametrically opposite po...

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  16. Kirchhoff's second law is the consequence of law of conservation of .....

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  17. For given Wheatstone's network for being balanced, the value of resist...

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  18. In the measurement of resistance by meter bridge, the end error can be...

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  19. E.m.f. can be measured by

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  20. The formula for internal resistance of a cell

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