The work done for rotating a magnet with magnetic dipole moment m through `90^@` from its magnetic meridian is n times the work done to rotate it through `60^@`. Find the value of n.

The work done by a magnetic field on moving charge is

A magnet of magnetic dipole moment 2Am2 is deflected through 30^@ from the direction of a magnetic field of induction 2frac(Wb)(m^2) . Find the magnitude of the torque.

Define magnetic dipole moment (m) and state its SI unit and dimension?

A bar magnet of magnetic moment 200 A-m^(2) is suspended in a magnetic field of intensity 0.25 N//A-m . The couple required to deflect it through 30^(@) is

The ratio of magnetic dipole moment of an electron of charge e and mass m in Bohr's orbit in hydrogen to its angular momentum is

A bar magnet of geometric length 18 cm has pole strength 100 A-m. Find the magnetic dipole moment of a bar magnet?

A short magnetic dipoles has magnetic moment 0.5 Am^2 . Calculate its magnetic field at a distance of 20cm from the center of magnetic dipole on the axis.

A magnet 10 cm and having a pole strength of 8 units is deflected through 45^(@) from the magnetic meridian. If the earth's magnetic field is 0.32 oersted, value of the deflecting couple in dynes cm will be

A short bar magnet has magnetic moment 20 Am^2 . The axis of the magnet is in the magnetic meridian with the south pole pointing north. The horizontal component of earth's magnetic field at that place is 3 xx 10^-5 T. Find the point on the axis of the magnet at which the resultant magnetic field is zero, [such a point is called a neutral point].

A short bar magnet is placed in an external magnetic field of 700 gauss. When its axis makes an angle of 30^@ with the external magnetic field, it experiences a torque of 0.014Nm. Find the magnetic moment of the magnet and the work done in moving it from the most stable to most unstable position.