A domain in ferromagneticiron isin the form of a cube of side 1 pm. Estimate the number of iron atoms in the domain maximum possible dipole moment and magnetization of the domain. The molecular mass of iron is 55frac(g)(mole) and density is `7.9 frac(g)(cm^3)`. Assume that each iron atom has a dipole moment of `9.27xx10^(-24) Am^2`.

A domain in ferromagnetic iron is in the form of a cube of side length 1 xx 10^-6 m . Estimate the number of iron atoms in the domain, the maximum possible dipole moment and magnetization of the domain. Given: density 7.9frac(g)(cm^3) , molecular mass of iron = 55 g/ mole. Assume each atom has a dipole moment of 9.27 xx 10^-24 Am^2 .

A bar magnet made of steel has magnetic moment of 2.5 Am^2 and a mass of 6.6 xx 10^-3 kg .If the density of steel is 7.9 xx 10^3 (kg)/m^3 , find the intensity of magnetisation of the magnet.

A paramagnetic gas has 2.0xx10^26 frac(atoms)(m^3) with atomic magnetic dipole moment of 1.5xx10^-23 A m^2 each. The gas is at 27^@C . (Find the maximum magnetization intensity of this sample.

An electron in an atom revolving round the nucleus in a circular orbit of radius 5.3 xx 10^-11 m with a speed of 2xx10^6 frac(cm)(s) . Find the resultant orbital magnetic moment and angularmomentum of electron. (Charge on electron e =1.6xx10^-19C , mass of electron m = 9.1 xx 10-31 kg )

A paramagnetic gas has 2.0xx10^26 frac(atoms)(m^3) with atomic magnetic dipole moment of 1.5xx10^-23 A m^2 each. The gas is at 27^@C . (If the gas in this problem is kept in a uniform magnetic field of 3T, is it possible to achieve saturation magnetization? Why?

An element with molar mass 27/mol forms cubic unit cell with edge length 405 pm. If density is given 2.7 g/cm^3 find the type of cubic unit cell it forms. We try to find the no. of atoms in each unit cell.