Home
Class 12
PHYSICS
The number of electrons flowing in a cur...

The number of electrons flowing in a current carrying circular coil per second having area of `2m^(2)` and magnetic moment of `8" A m"^(2)` is

A

`2.5xx10^18`

B

`5xx10^18`

C

`6.25xx10^18`

D

`25xx10^18`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • Magnetic Materials

    CHETANA PUBLICATION|Exercise EXERCISE|74 Videos

  • Magnetic Fields due to Electric Current

    CHETANA PUBLICATION|Exercise Exercise|96 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    CHETANA PUBLICATION|Exercise Exercise|91 Videos

Similar Questions

Explore conceptually related problems

The direction of magnetic moment of a current carrying circular coil is

Define magnetic dipole moment for a current carrying circular loop.

Define magnetic dipole moment of a current carrying coil.

A torque of 25 N m acts on a current carrying coil of area 5 m^(2) and magnetic moment 2 A m^(2) in a magnetic field of induction 2Wb//m^(2) . The angle between normal to coil and magnetic induction is 30^(@) . Then value of current is

The magnetic moment of a current (i) carrying circular coil of radius (r) and number of turns (n) varies as

The magnetic induction at the centre of a current carrying circular coil of radius 10cm is 5sqrt(5) times the magnetic induction at a point on its axis. The distance of the point from the centre of the coil in m is

The ratio of magnetic field at the centre of a current carrying circular coil to its magnetic momnts is x. If the current and radius both are doubble the new ratio will become

Define Magnetic dipole moment of a current carrying coil State its SI unit and dimension.

Derive an expression for magnetic induction at a point along axis of current carrying circular coil .

Obtain an expression for magnetic induction at the centre of current carrying circular coil.