Home
Class 12
PHYSICS
In LCR series combination R = 10 Omega, ...

In LCR series combination R = `10 Omega`, L = 1 mH, C = `2 muF`. Determine :- resonant frequency,

Promotional Banner

Topper's Solved these Questions

  • AC CIRCUITS

    CHETANA PUBLICATION|Exercise Exercise|122 Videos
  • Current Electricity

    CHETANA PUBLICATION|Exercise Exercise|92 Videos

Similar Questions

Explore conceptually related problems

In LCR series combination R = 10 Omega , L = 1 mH, C = 2 muF . Determine :- the current in the circuit when an alternating voltage of 10 mV operating at the resonant frequency is applied to the series combination.

An alternating e.m.f. of peak value 110 V andfrequency 50 Hz is connected across LCR series circuit with R = 100 Omega , L = 10 mH, C = 25 muF . Calculate the inductive reactance, capacitive reactance and impedance.

An A.C. voltage of r.m.s. value 1 V is applied to a parallel combination of inductor L = 10 mH, and capacitor 4 muF . Calculate the resonant frequency and current through each branch and resonance.

An A.C. voltage of r.m.s. value IV is applied to a parallel combination of inductor L = 10mH and capacitor C = 4muF . Calculate the resonant frequency and current through each branch at resonance.

In series LCR circuit R = 4Omega , L = 0.2 H and C = 0.1 F, at resonance impedance is

A series LCR circuit with R=20 Omega ,L=1.5 H and C = 35 mu F is connected to a variable frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit , what is the average pourer transferred to the circuit in one complete cycle?

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :- maximum current

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :- impedance of the circuit

A sinusoidal voltage of peak value 283V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 muf . Find:-The impedance of the circuit

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :-average power delivered to the circuit.

CHETANA PUBLICATION-AC CIRCUITS-Exercise
  1. In LCR series combination R = 10 Omega, L = 1 mH, C = 2 muF. Determine...

    Text Solution

    |

  2. A LCR series circuit has the impedance of 240 ohm. If R = 120 Omega, f...

    Text Solution

    |

  3. In LCR series circuit a voltmeter is connected in turn acrosstheendsof...

    Text Solution

    |

  4. What inductive reactance will a 1/piH inductor have at the 50 Hz frequ...

    Text Solution

    |

  5. What is the period of a 50 Hz voltage wave?

    Text Solution

    |

  6. An inductor draws 5A of current at 230 V, 50 Hz. Find the value of ind...

    Text Solution

    |

  7. A capacitor draws 10 Aof current at 230 V, 50 Hz. Find the capacitive ...

    Text Solution

    |

  8. A circuit connected to a 200 V supply takes a current of 4.8 A. If the...

    Text Solution

    |

  9. A voltage e = 50 sqrt2 sin 314.0 t volt is applied across a 10 ohm res...

    Text Solution

    |

  10. A voltage e = 50 sqrt2 sin 314.0 t volt is applied across a 10 ohm res...

    Text Solution

    |

  11. A voltage e = 50 sqrt2 sin 314.0 t volt is applied across a 10 ohm res...

    Text Solution

    |

  12. A 2H inductor of negligible resistance is connected to a 50 V, 50 Hz p...

    Text Solution

    |

  13. A 2H inductor of negligible resistance is connected to a 50 V, 50 Hz p...

    Text Solution

    |

  14. A peak value of alternating voltage is 494.97 V. Find reading on voltm...

    Text Solution

    |

  15. In a purely inductive ac circuit L = 25 mH and peak voltage of ac supp...

    Text Solution

    |

  16. An inductor has a reactance of 125.6 Omega at 200 Hz. What is the indu...

    Text Solution

    |

  17. An alternating e.m.f. given by e = 50 sin 314t is applied to a pure re...

    Text Solution

    |

  18. An alternating e.m.f. given by e = 50 sin 314t is applied to a pure re...

    Text Solution

    |

  19. An alternating e.m.f. given by e = 50 sin 314t is applied to a pure re...

    Text Solution

    |

  20. An alternating e.m.f. given by e = 50 sin 314t is applied to a pure re...

    Text Solution

    |

  21. A 60 watt lamp is connected to an alternating e.m.f. of peak value 230...

    Text Solution

    |