In a series LCR circuit, R = `20 Omega`, C = `10 muF` and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :-average power delivered to the circuit.

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :- maximum current

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :- impedance of the circuit

In a series LCR circuit, R = 20 Omega , C = 10 muF and L = 25 mH.The frequency of applied a.c. e.m.f. of 240 volt (peak) is 50 Hz. Calculate :-phase angle between the current and the voltage

In series LCR circuit R = 4Omega , L = 0.2 H and C = 0.1 F, at resonance impedance is

In LCR series combination R = 10 Omega , L = 1 mH, C = 2 muF . Determine :- resonant frequency,

A capacitor of 20 muF is connected in series with a 25 Omega resistance to peak e.m.f. 240 V, 50 Hz A.C. Calculate:-impedance of the circuit

A capacitor of 20 muF is connected in series with a 25 Omega resistance to peak e.m.f. 240 V, 50 Hz A.C. Calculate:-the capacitive reactance of the coil

A series LCR circuit with R=20 Omega ,L=1.5 H and C = 35 mu F is connected to a variable frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit , what is the average pourer transferred to the circuit in one complete cycle?

An emf e = e_0 sin omega t applied to a series L-C-R circuit derives a current I = I_0 sin omega t in the circuit. Deduce the expression for the average power dissipated in the circuit.