Radiation of wavelength `4500overset@ A` is incident on a metal having work function 2.0 eV. Due to the presence of a magnetic field B, the most energetic photoelectrons emitted in a direction perpendicular to the field move along a circular path of radius 20 cm. What is the value of the magnetic field B?

A photon of energy E ejects a photoelectron from a metel surface whose work function is phi_(0) . If this electron enters into a unifrom magnetic field of induction B in a direction perpendicular to the field and describes a circular path of radius r, then the radius r, is given by, (in the usual notation)

A uniform magnetic field acts right angles to the direction of motion of electrones. As a result, the electron moves in acircular path of radius 2 cm. If the speed of electrons is doubled, then the radius of the circular path will be

A beam of a-particles moving along +x axis, experiences a force due to a magnetic field along +y axis.What is the direction of magnetic field?

An electron and proton moving with same speed enter the same magnetic field region at right angles to the direction of the field.For which of the two particles will the radius of circular path be smaller ?

A proton is moving along positive x-axis in the presence of uniform magnetic field along positive y-axis. What is the direction of force acting on ?

A long solenoid carrying a current produces a magnetic field B along the axis. If the number of turns per cm is tripled and the current is halved, then the new value of the magnetic field will be

A piece of straight wire has mass 20g and length lm. It is to be levitated using a current of 1A flowing through. A perpendicular magnetic field B in a horizontal direction is applied what must be the magnetic field B? take g = 9.8 m//s^2

What will be the path of a charged particle moving along the direction of a uniform magnetic field?