During a seminar session in the class , the presenter argued that equal amounts of both `H_2` and `N_2` on heating at constant pressure will expand in the same rate. Another student objected this argument by saying that they will expand differently since their molecular masses are different .
c)State the law and give its mathematical expresssion.

During a seminar session in the class , the presenter argued that equal amounts of both H_2 and N_2 on heating at constant pressure will expand in the same rate. Another student objected this argument by saying that they will expand differently since their molecular masses are different . a)Who is correct in your opinion ?

During a seminar session in the class , the presenter argued that equal amounts of both H_2 and N_2 on heating at constant pressure will expand in the same rate. Another student objected this argument by saying that they will expand differently since their molecular masses are different . b) Which law helped you to reach the answer ?

What amount of heat must be supplied to 2.0 × 10^-2 kg of nitrogen (at room temperature) to raise its temperature by 45°C at constant pressure? (molecular mass of N_2=28 , R=8.3Jmol^-1K^-1 )

A) For N_(2) O gas, the difference in specific heats at constant pressure and at constant volume is equal to 0.04545 cal/g B) Entropy of a perfectly crystalline solid is zero at absolute zero of temperature C) Standard Gibbs energy of formation and standard enthalpy of formation are zero for elements in standard state D) T(deltaS^(0) _("total") = Delta G Which of these statements are true?

For one-electron species, the wave number of radiation emitted during the transition of electron from a higher energy state (n_(2)) to a lower energy state (n_(1)) is given by: bar v =(1)/(lamda)=R_(H) xx Z^() ((1)/(n_(1)^(2)) (1)/(n_(2)^(2))) where R_(H)=(2 pi m_(s) k^(2) c^(4))/(h^(3) c) is Rydberg constant for hydrogen atom. Now, considering nuclear motion, the accurate measurement would be obtained by replacing mass of electron (m_(e)) by the reduced mass (mu) in the above expression, defined as mu =(m_(n)xx m_(e))/(m_(n) +m_(e)) where m_(n) = mass of nucleus. For Lyman series, n_(t) =1 (fixed for all the lines) while n_(2) = 2, 3, 4 .... For Balmer series: n_(1) = 2 (fixed for all the lines) while n_(2) = 3,4,5 .... If proton in hydrogen nucleus is replaced by a positron having the same mass as that of an electron but same charge as that of proton, then considering the nuclear motion, the wavenumber of the lowest energy transition of He+ ion in Lyman series will be equal to