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A point of application of a force vec F=...

A point of application of a force `vec F= 5hati - 3hatj +2hatk` is moved from `vec r_1= 2hati + 7hatj +4hatk` to `vec r_2 =-5hati + 2hatj +3hatk`. The work done is

A

`-22 units`

B

22 units

C

11 units

D

0 units

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The correct Answer is:
A
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MBD PUBLICATION-VECTOR ANALYSIS-QUESTION BANK
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