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If abs(vecA+vecB)=abs(vecA-vecB) find t...

If `abs(vecA+vecB)=abs(vecA-vecB)` find the angle between `vecA` and `vecB`.

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Let `theta` be the angle between `vecA` and `vecB`
Given `abs(vecA+vecB)=abs(vecA+vecB)=abs(vecA-vecB)` `therefore abs(vecA+vecB)^2=abs(vecA-vecB)^2`
`vecAcdotvecA+vecBcdotvecB+2vecAcdotvecB=vecAcdotvecA+vecBcdotvecB-2vecAcdotvecB or `4vecAcdotvecB`=0
since A&B are non zero `costheta=0 or `theta=90^@`
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