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If vecA=3hati+4hatj and vecB=7hati+24hat...

If `vecA=3hati+4hatj` and `vecB=7hati+24hatj` find a vector having the same magnitude as `vecB` and parallel to `vecA`.

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Now `vecAxxvecB`=(hati+2hatj+3hatk)xx(2hati-hatj+hatk)=-hatk-hatj-4hatk+2hatj+6hatj+3hati=5hati+5hatj-5hatk`
`abs(vecAxxvecB)=Absintheta` we get `sin theta = abs(vecAxxvecB)//AB`
since A=`sqrt(1+4+9)=sqrt14` and B=sqrt(4+1+1)=sqrt6`
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MBD PUBLICATION-VECTOR ANALYSIS-QUESTION BANK
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