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A ball Is projected horizontally from th...

A ball Is projected horizontally from the top of a tower with velocity 4m/s. The velocity of the ball after 0.7s (g = 10`m/s^2` ) is

A

11m/s

B

10m/s

C

8m/s

D

3m/s

Text Solution

Verified by Experts

The correct Answer is:
A
velocity of the ball after time
t = `sqrt(v^2x +v^2y) =sqrt(4^2+ g t^2)= sqrt(16+(10xx7)^2)` = 8m/s.
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